Oxalic acid and water mixture is added to potassium permanganate in different wa

Question

Oxalic acid and water mixture is added to potassium permanganate in different ways as above. The time for the mixture to turn yellow is recorded as well.

#1 Fill the blanks in the last column

#2 Determine the order of the reaction, order with respect to Potassium Permanganate, and with respect to Oxalic acid.

#3 Write Rate law expression and fine the Value of k

Table 1. Order of the Reaction. Any changes in reaction rate are due to changes in concentrations Trial # | mLs HaCaO4 5.0 5.0 10.0 mLs H20 7.5 5.0 2.5 mLs KMnO4 2.5 5.0 2.5 Time (sec) Rate (M/s) 3 2O

Explanation / Answer

5 H2C2O4 + 2 KMnO4 = 10 CO2 + K2O + 2 MnO + 5 H2O is the reaction preocess
reaction rate
r=-1/5d[H2C2O4]/dt=-1/2d[KMNO4]/dt=-1/5[H20]/dt=1/10d[CO2]/dt=1d[K2O]/dt=1/2d[MNO]/dt
r= so in the table they are directly given the concentration of reactents
1) rate =1/2d[KMNO4]/dt=1/2*2.5/387=3.2X10^-3
2)rate =1/2*5.0/330=7.5X10^-3
3)rate=1/2*2.5/240 =5.2*10^-3
order of the reaction =k[KMNO4]^2[H2C2O4]^5
reaction rate is 7 over all
2 wrt kmno4
5 wrt H2C2O4

3)for the above reaction reaction rate wrt kmno4 is =k[KMNO4]^2
we already know the rate of the above reaction wrt KMNO4
eauate the rate wrt KMNO4 ,using concentartion of KMNO4
you will get k value

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