(1) For the precipitates that formed, write the complete molecular reaction, the
ID: 838041 • Letter: #
Question
(1) For the precipitates that formed, write the complete molecular reaction, the complete (full) ionic equation and lastly, the net ionic equation for the following:
a) BaCl2 + NaIO3 -->
b) BaCl2 + NaOH -->
c) BaCl2 + Al2(SO4)3 -->
d) Zn(NO3)2 + NaOH -->
e) NaOH + Al2(SO4)3 -->
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(2) Write a balanced molecular reaction, the complete (full) ionic equation and lastly, the net ionic equation showing the dissolution reaction for each of the precipitates that was soluble in HC2H3O2 (aq):
a) BaCl2 + NaOH -->
b) Zn(NO3)2 + NaOH -->
Please make sure to write out the molecular reactions, complete (full) equations AND the net ionic equations, thank you!
Explanation / Answer
Question 1
(a) Molecular reaction:
BaCl2 (aq) + 2NaIO3 (aq) ---> Ba(IO3)2 (s) + 2NaCl (aq)
Full ionic
Ba2+ (aq) + 2Cl- (aq) + 2Na+ (aq) + 2IO3- (Aq) ---> Ba(IO3)2 (s) + 2Cl- (aq) + 2Na+ (aq)
Net ionic
Ba2+ (aq) + 2IO3- (Aq) ---> Ba(IO3)2 (s)
-----
(b) Molecular:
BaCl2 (aq) + 2NaOH (aq) ---> Ba(OH)2 (s) + 2NaCl (aq)
Full ionic
Ba2+ (aq) + 2Cl- (aq) + 2Na+ (aq) + 2OH- (aq) ---> Ba(OH)2 (s) + 2Cl- (aq) + 2Na+ (aq)
Net ionic:
Ba2+ (aq) + 2OH- (aq) ---> Ba(OH)2 (s)
---
(c) Molecular:
3BaCl2 (aq) + Al2(SO4)3 (aq) ---> 3BaSO4 (s) + 2AlCl3 (aq)
Full ionic:
3Ba2+ (aq) + 6Cl- (aq) + 2Al3+ (aq) + 3SO42- (aq) --> 3BaSO4 (s) + 2Al3+ (aq) + 6Cl- (aq)
Net ionic:
3Ba2+ (aq) + 3SO42- (aq) --> 3BaSO4 (s)
---
(d) Molecular
Zn(NO3)2 (aq) + 2NaOH (aq) ---> Zn(OH)2 (s) + 2NaNO3 (aq)
Full ionic:
Zn2+ (aq) + 2NO3- (aq) + 2Na+ (aq) + 2OH- (aq) --> Zn(OH)2 (s) + 2NO3- (aq) + 2Na+ (aq)
Net ionic:
Zn2+ (aq) + 2OH- (aq) --> Zn(OH)2 (s)
---
(e) Molecular
6NaOH (aq) + Al2(SO4)3 (aq) ---> 2Al(OH)3 (s) + 3Na2SO4 (aq)
Full ionic:
6Na+ (aq) + 6OH- (aq) + 2Al3+ (aq) + 3SO42- (aq) ---> 2Al(OH)3 (s) + 6Na+ (aq) + 3SO42- (aq)
Net ionic:
2Al3+ (aq) + 6OH- (aq) ---> 2Al(OH)3 (s)
-------------------------------------------------------------
Question 2
You don't really write molecular / full ionic / net ionic equations for dissolution reactions. They really just look this like :
a) The precipitate was Ba(OH)2 (s). The dissolution reaction is:
Ba(OH)2 (s) ---> Ba2+ + 2OH-
b) The precipitate was Zn(OH)2 (s). The dissolution reaction is:
Zn(OH)2 (s) ---> Zn2+ + 2OH-
Hope this was helpful!
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