1. If you mixed 100 mL of water at 20C with 100mL of water at 40C in a perfect (

Question

1. If you mixed 100 mL of water at 20C with 100mL of water at 40C in a perfect (adiabatic) container, you would expect to end up with 200mL of water at 30C.

?Tcold water = 10C

mcold water = mhot water

?Thot water = -10C

Cpis constant for both liquids.

Prove that the heat capacity, B, for an adiabatic container is ZERO.

2. In less-than-perfect system, some of the heat that should have been transferred from teh hot water to the cold water is lost to the calorimeter and to the surroundings.

a) Is the magnitude of ?Tcold water now less or more than in our perfect system?

b) Is the magnitude of ?Thot water now less or more than in our perfect system?

c) Is B a positive or negative quantity? What would it mean for a substance to have a negative heat capacity?

3. Classify the following systems as open, closed or adiabatic:

a) An ideal thermos bottle

b) A hot water bottle

c) A hot bottle that leaks

Please answer all three questions. those might be easy but i didn't study..

Thanks!!

Explanation / Answer

Heat capacity of an adiabatic container is zero since it does not change the temp.

If it has heat capacity then some amount of heat may be lost

2)

a) the magnitude of tmp change in cold water become less

b) the magnitude of temp change in hot water become more

c) B should be a positive quantity

3)

a) an ideal thermos--- adiabatic

b) a hot water bottle---- closed

c) a hot bottle that leaks---- open

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