In the following chemical reaction, 2 mol of A will react with 1 mol of Bto prod

Question

In the following chemical reaction, 2 mol of A will react with 1 mol of Bto produce 1 mol of A2 B without anything left over: But what if you're given 2.8 mol of A and 3.2 mol of B? The amount of product formed is limited by the reactant that runs out first, called the limiting reactant. To identify the limiting reactant, calculate the amount of product formed from each amount of reactant separately: Notice that less product is formed with the given amount of reactant A. Thus, A is the limiting reactant, and a maximum of 1.4 mol of A2 B can be formed from the given amounts. with 1 mol of Bto produce 1 mol of A2 B without anything left over: But what if you're given 2.8 mol of A and 3.2 mol of B? The amount of product formed is limited by the reactant that runs out first, called the limiting reactant. To identify the limiting reactant, calculate the amount of product formed from each amount of reactant separately: Notice that less product is formed with the given amount of reactant A. Thus, A is the limiting reactant, and a maximum of 1.4 mol of A2 B can be formed from the given amounts. You are given 11.0g of aluminum and 16.0g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 11.Og of aluminum? Express your answer to three significant figures and include the appropriate units. Submit Hints Mv Answers Give Up Review Part Enter your answer using dimensions of amount of substance. Part B If you had excess aluminum, how many moles of aluminum chloride could be produced from 16.0g of chlorine gas, Cl2 ? Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

A. moles of aluminium=11/27

moles of AlCl3 that can be produced from this =11/27=0.407

B.moles of Cl2=16/(2*35.5)=0.2253

moles of AlCl3 that can be produced from this =(2/3)*0.2253=0.15023

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