1. Three elements have the electron configurations 1s 2 2s 2 2p 6 3s 2 3p 6 4s 1
ID: 840336 • Letter: 1
Question
1. Three elements have the electron configurations 1s22s22p63s23p64s1, 1s22s22p63s23p5, and 1s22s22p63s1. The first ionization energies of these elements (not in the same order) are 0.496, 1.256, and 0.419 MJ/mol. The atomic radii are 99, 227, and 186 pm. Identify the three elements, and match the appropriate values of ionization energy and atomic radius to each configuration.
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2. Consider the ground state of mercury, Hg.
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3. Which of the following are possible sets of quantum numbers for an electron in an atom? Click the boxes with the correct answers.
(Select all that apply.)
n = 5, l = 2, ml = -2, ms = +1/2
n = 2, l = 0, ms = 0
n = 2, l = 1, ml = 0, ms = 0
n = 7, l = 6, ml = -6, ms = -1/2
n = 7, l = 3, ml = -4, ms = +1/2
Electron Configuration Element Symbol First Ionization Energy (MJ/mol) Atomic Radius (pm) 1s22s22p63s23p64s1 _______________ ________________ _______________ 1s22s22p63s23p5 _______________ _______________________________
1s22s22p63s1 ______________ _________________________________
Explanation / Answer
1s22s22p63s23p64s1K 0.419MJ 227pm
1s22s22p63s23p5 Cl 1.256 MJ 99pm
1s22s22p63s1 Na 0.496 MJ 186pm
How many electrons have l = 1 as one of their quantum numbers = 3
How many electrons have ml = 0 are = 6
How many electrons have ml = +1 are = 5
possible states:
n = 5, l = 2, ml = -2, ms = +1/2
n = 7, l = 6, ml = -6, ms = -1/2
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