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SOME OF THE ANSWERS IN THE PICTURES ARE WRONG. IGNORE THE FIRST BALANCE. Balance

ID: 840427 • Letter: S

Question

SOME OF THE ANSWERS IN THE PICTURES ARE WRONG. IGNORE THE FIRST BALANCE.

Balance the following chemical equation using the smallest whole numbers (NO FRACTIONS) Use numbers only, not words. For example, wnte "3", not "three", IF THE COEFFICIENT IS 1. DO NOT LEAVE IT BLANK !: HINT: the reaction below is an oxidation-reduction reaction For the following reaction: 2H2S + SO2 rightarrow 3S + 2H2O Before 7.50 g ofH2S reacts with 12.75 g of SO2, the initial amount of moles of H2S are mol and the initial amount of moles of SO2 are moL (USE PROPOR SIG FIGS FOR EACH!) Once they react, which is the limiting reagent? (Type H2S if you think it is H2S OR SO2 if you think it is SO2) How many moles of H2O will be produced? mol How many grams of S will be produced? g

Explanation / Answer

moles of H2S = 7.5/34

=0.22

moles of SO2=12.75/64

=0.199

so, the limitin reagent is H2S.so,

moles of H2O produced=moles of H2S = 0.22

mass of S produced = 1.5*32*0.22

=10.56 grams