Use valence bond theory to describe the bonding in the methanol (CH3OH) molecule
ID: 840943 • Letter: U
Question
Use valence bond theory to describe the bonding in the methanol (CH3OH) molecule.
A. There are two central atoms, C and O. The C atom is bound to three H atoms and to one O atom, whereas the O atom is bound to one H atom and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the O atom's orbitals are hybridized as sp orbitals. The electron-group geometries around C atom and the O atom are tetrahedral and linear, respectively. There are 5 sigma bonds and 0 pi bonds in this molecule.
B. There are two central atoms, C and O. The C atom is bound to three H atoms and to one O atom, whereas the O atom is bound to one H atom and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the O atom's orbitals are hybridized as sp2 orbitals. The electron-group geometries around C atom and the O atom are tetrahedral and trigonal planar, respectively. There are 6 sigma bonds and 0 pi bonds in this molecule.
C. There are two central atoms, C and O. The C atom is bound to three H atoms and to one O atom, whereas the O atom is bound to one H atom and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the O atom's orbitals are hybridized as sp3 orbitals. The electron-group geometries around C atom and the O atom are both tetrahedral. There are 5 sigma bonds and 0 pi bonds in this molecule.
Explanation / Answer
There are two central atoms, C and O. The C atom is bound to three H atoms and to one O atom, whereas the O atom is bound to one H atom and one C atom. The C atom's orbitals are hybridized as sp3 orbitals, and the O atom's orbitals are hybridized as sp orbitals. The electron-group geometries around C atom and the O atom are tetrahedral and linear, respectively. There are 5 sigma bonds and 0 pi bonds in this molecule.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.