A solution of lithium hydroxide is mixed with a solution of calcium chloride, an

Question

A solution of lithium hydroxide is mixed with a solution of calcium chloride, and a precipitate of solid calcium hydroxide forms. What are the spectator ions in this reaction?

Li+ and Ca2+

Ca2+ and Cl-

Ca2+ and OH-

Li+ and Cl-

Not enough information is given.

Consider the following balanced reaction:

2 C2H6 (g) + 7 O2 (g) ? 4 CO2 (g) + 6 H2O (g)

If 1.0 mol of C2H6 is reacted in excess oxygen, how many mol of CO2 will be produced?

1.0 mol CO2

2.0 mol CO2

3.0 mol CO2

4.0 mol CO2

6.0 mol CO2

Consider the following balanced reaction:

N2 (g) + 3 H2 (g) ? 2 NH3 (g)

If 1.25 mol of N2 and 1.50 mol of H2 are present, how many mol of NH3 can be produced?

1.00 mol NH3

1.25 mol NH3

1.50 mol NH3

2.00 mol NH3

2.75 mol NH3

A student calculates that 9.12 g of salicylic acid should be produced by a reaction.  
Her actual yield turns out to be 2.09 g of salicylic acid. What is the percent yield for her reaction?

77.3 %

114 %

22.9 %

33.4 %

0.334 %

What mass of NaOH (in g) is necessary to make 1.35 L of a 0.350 M NaOH solution?

14.2 g

39.3 g

18.9 g

0.350 g

40.0 g

Li+ and Ca2+

Ca2+ and Cl-

Ca2+ and OH-

Li+ and Cl-

Not enough information is given.

Explanation / Answer

1.A spectator ion is an ion that exists as a reactant and a product in a chemical equation. Spectator ions canbe observed in the reaction of aqueous solutions but does not affect the equilibrium.so answer is Li+ and Cl-

2.) 2.0 mol CO2 wold be produced since 4(co2)/2(c2h6)=2

2 mol of C2H6 gives 4 mol of CO2
so,
1 mol of C2H6 will give 2 mol of CO2

3.)1 mol of N2 requires 3 mol of H2
so 1.25 mol of N2 will require 3.75 moleof H2

H2 is limiting reagent.

3 moles of H2 gives 2 mol of NH3
1.5 mol of H2 will give 1 mol of NH3

4.)
% Yield = (actual yield / theoretical yield) x 100%

= 2.09 *100/9.12
                 = 22.9 %

5.)
M(Molarity) = Mol (moles)/Volume (L)

Molar mass of NaOH= 23+16+1=40 gm
Molarity= mass/(molar mass *volume)
0.35= mass/(40*1.35)
Mass=18.9 gm

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