help with problem Question 6 (1 point) An experiment similar to the one performe

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help with problem

Question 6 (1 point) An experiment similar to the one performed in this lab was carried out to determine the Ksp of PbCl2, MM 278.10 g/mol (PbCl Pb2+ 2 CIT) The dissolved chloride in the filtered solution was quantitatively precipitated as AgCl by the addition of excess AgNO3 solution. The solid AgCl was filtered, dried, and weighed. The results were: Temperature of the solution 20.2°C, Volume of PbCl2 solution analyzed 20.40 mL, Mass of dry AgCl 0.3478 grams. What was K of PbCl2? sp

Explanation / Answer

mass of dry AgCl=0.3478g

moles of AgCl=0.3578g/143.5g/mole=0.00249moles

moles of Cl-=moles of AgCl=0.00249moles

[Cl-]=0.00249moles/0.02040L=0.122M

moles of Pb2+=(moles of Cl-)/2=0.001245moles

[Pb2+]=0.001245moles/0.0204L=0.061M

PbCl2<==> Pb2+ + 2Cl-

ksp(PbCl2)=[Pb2+][Cl-]2=(0.061)(0.122)2=0.0009084moles3/L3

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