Given this data, determine the moles of base in antacid sample and the moles of

Question

Given this data, determine the moles of base in antacid sample and the moles of base per gram of antacid. Determination of an Unknown Metal Identity of antacid sample:Alka-seltzer Active ingredient(s) in sample:NaHCO3 Trial 1 Trial 2 Trial 3 Mass of antacid: .198 g .204 g .201 g Concentration of HCL solution used:0.09723 M Volume of HCL added: 25 ml 25 ml 25 ml Total moles of HCI added: .0024 mol .0024 mol .0024 mol Concentration of NaOH titrant: 0.0764 M Initial buret reading: 0 0 14.6 Final buret reading:14.6 ml 14.6 ml 39.2 ml Volume of NaOH in back-titration: 14.6 14.6 14.6 Moles of NaOH in back-titration: Moles of base in antacid sample: Moles of base per gram of antacid: Average moles of base per gram of antacid: Deviation: Relative average deviation: Clearly show all calculations for one trial: .09723 mol/.025/1L =.0024 mol

Explanation / Answer

The first thing you always do is balance the equation.

2HCl + CaCO3 ===> H2O + CaO + CO2 (I'll let you figure out the states.)

What the equation tells you is that for every two moles of HCl, you need 1 mole of CaCO3 which is the base in this case.

2 moles HCl requires 1 mole of CaCO3
0.0025 moles of HCl requires x moles of CaCO3

2/0.0025 = 1 / x
2x = 0.0025
x = 0.00125 moles of CaCO3

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