1-If 6.022 x 10 23 molecules of N 2 react according to the equation: N 2 + 3H 2

ID: 843232 • Letter: 1

Question

1-If 6.022 x 1023 molecules of N2 react according to the equation: N2 + 3H2 ? 2 NH3

the total number of molecules of ammonia produced is 1) 1.00 2) 2.00 3) 6.022 x 1023 4) 1.20 x 1024

2. A buffer solution can be made with which of the following combinations of compounds?

I) NaF and HF II) Na2S and H2S III) NaNO3 and HNO3

1) I only 2) I and II only 3) II and III only 4) I, II or III

3-How many moles of CaCO3 are represented by 212 g of CaCO3? SHOW YOUR WORK!!

6.022 x 1023 molecules of N2 = 1 mole

1 mole of N2 gives 2 moles of NH3

Molecules = 2 * 6.022 x 1023

=> 4) 1.20 x 1024

4) I, II or III

Buffer is formed by weak acid and its conjugate salt. Here Na2S and H2S satisfy that so option 4 is right

1 mole of CaCO3 has mass = 100 grams

212 grams = 212/100 = 2.12 moles

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