70% LD 12:49 AM iPad angel spcollege.edu Homework Help Ask A Question Che CHM204

Question

70% LD 12:49 AM iPad angel spcollege.edu Homework Help Ask A Question Che CHM2046 General Chemistry ll n Cl practice 1.pdf 24. The reaction 2NOBr 2NO +Br2 exhibits the rate law 2 ADNOBrd Rate icLNOBrd where k 1.0 x 10 M s 1 at 25OC. This reaction is run where the initial concentration of NOBr (LNOBrlo is 1.00 x 10 M. The [NO] after 1.00 hour has passed is A) 3.6 x 10-4 M B) 9.9 x 10-3 M C) 9.7 x 10-3 M D) 1.0 x 10 M E) none of these 25. The reaction is first order in N205. For this reaction at 450C, the rate constant k 1.0 x 10 s s 1, where the rate law is defined as AIN2Os Rate At For a particular experiment (IN205]0 31.0 x 10 MD, calculate IN2O5 after 3.5 x 105 seconds. A) 3.5 M B) 1.0 x 10-3 M C) 3.0 x 10-5 M D) 0 M E) 10 M 26. The decomposition of ozone may occur through the two-step mechanism shown: step 1 O3 O2+O step 2 O2 +O 20 The oxygen atom is considered to be a(n) A) reactant B) product C) catalyst D) reaction intermediate E) activated complex

Explanation / Answer

24) 2NOBr ---> 2NO + Br2

for 2 moles of NOBr, 2moles of NO are produced.

:. 1 mole of NOBr produces 1 mole of NO.

K * [NOBr]^2 = -delta[NOBr] / delta t

:. 10^-5 * (10^-1)^2 = delta [NOBr] / 3600                    (because 1 hour has 3600 seconds)

:. delta[NOBr] = 0.00036 moles

:. [NO] = 3.6 * 10^-4

A

25) 2N2O5 ---------> O2 + 4NO2

K[N2O5] = - delta[N2O5]/ delta t

10^-5 * 10^-3 = delta[N2O5] / 3.5 * 10^5

:. delta [N2O5] = 0.0035 = 3.5 * 10^-3

:. [N2O5] = 10^-3 - 3.5 * 10^-3

which is negative.

So it means all of the N2O5 has been converted to O2 + NO2.

So [N2O5] = 0 M

D

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