The figure at the right illustrates the inverse relationship between oxygen and

Question

The figure at the right illustrates the inverse relationship between oxygen and proton binding to hemoglobin, known as the Bohr effect. Oxyhemoglobin is more acidic because of salt bridges broken when oxygen binds. For purposes of calculation, hemoglobin can be modeled as a simple monoprotic buffer dissociating one proton per subunit as illustrated in the figure and in the following two equilibria: 8.0 = 7.8 Calculate the quantity (in mmol) of protons that will be released when 2.85 mmol of oxygen bind to deoxyhemoglobin at pH 7.4 and the pH then returns to 7.4, i.e. in going from point A to point B on the curve. nprotons= Number mmol

Explanation / Answer

[HA]/[A-]=10^(pK-pH)
[HHb]/[Hb]=10^(7.8-7.4)=2.51
fraction of HHb= 2.51/1+2.51=.715
nHHb= .715x 2.85= 2.03 mm

[HHbO2]/[HbO2]=10^(6.7-7.4)=.200
fraction HHbO2= .200/1+.002=.374mm

2.03-.374= 1.66

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