In this experiment a hot metal block at 100 o C is added to cold water in a calo

Question

In this experiment a hot metal block at 100oC is added to cold water in a calorimeter. The heat lost by the metal block equals the heat gained by the water and the two end up at the same temperature.

In one experiment, the mass of the metal block is 101 grams, the volume of water used is 87.9 mL, the temperature of the cold water extrapolated to the time of mixing is 18.8oC, and the temperature of the metal block and water extrapolated back to the time of mixing is 26.5oC.

How much heat is gained by cold water?

Explanation / Answer

assuming denity water = 1g/mL

mass water = 87.9 g
heat gained by water = 87.9 x 4.184 ( 26.5 - 18.8)= 2831.85 J

101 x specific heat ( 26.5 - 100) + 2831.85=0

specific heat = 0.381 J/g

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