Calculations The wieght of crucible lid off: 16.441g The wieght of crucible +lid

ID: 851050 • Letter: C

Question

Calculations

The wieght of crucible lid off: 16.441g

The wieght of crucible +lid :29.190g

The total wieght of crcible + lid +hydrate of BaCl2.xH2O: 32.271g

The total wieght of crcible + lid +hydrate of BaCl2.xH2O after heating:31.813

The total wieght of crcible + lid +hydrate of BaCl2.xH2O after second heating : 31.807 g .

1: what is the mass of original hydrate sample?

2:mass of anhydrous BaCl2 (mass remaining after heating without crucible and lid mass)?

3: mass lost upon heating?

4:%mass of water in the sample?

5:moles of water in your sample , moles of anhydrous salt in your sample , and mole ratio of water to salt?

1) mass of original hydrate sample - ( wt of crucible + lid + hydrate - wt of crucible + lid)

= 32.271 - 29.190= 3.081 g

2) mass of anhydrous BaCl2 - ( wt of crucible + lid + hydrate after 2nd heating - wt of crucible + lid)

= 31.807 -29.190 = 2,617

3) mass lost upon heating - 3.081 - 2.617 = 0.464g

4)% of water lost- 0.464/ 3.081 * 100 =15.06%

5) moles of water - 0.464 /18 = 0.025 ( no of moles = wt of solute in gms / molwt)

moles of anhydrous sample - 2.617 / 208.32 = 0.01479 ( mol wt of BaCl2 - 208.32 , of water -18 )

mole raio of water to anh .sample = 0.025 / 0.01479 =1.690

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