If 28 ml of a 0.537 M NaOH solution is needed to neutralize 20 mL of a carbonic
ID: 851204 • Letter: I
Question
If 28 ml of a 0.537 M NaOH solution is needed to neutralize 20 mL of a carbonic acid, H2CO3, solution, what is the molarity of the carbonic acid? [Write a balanced chemical reaction first.] ?If 28 ml of a 0.537 M NaOH solution is needed to neutralize 20 mL of a carbonic acid, H2CO3, solution, what is the molarity of the carbonic acid? [Write a balanced chemical reaction first.] ?
If 28 ml of a 0.537 M NaOH solution is needed to neutralize 20 mL of a carbonic acid, H2CO3, solution, what is the molarity of the carbonic acid? [Write a balanced chemical reaction first.] ?
Explanation / Answer
2) Equation:
2NaOH + H2CO3 ? Na2CO3 + 2H2O
2mol NaOH reacts with 1 mol H2CO3
Mol NaOH in 28mL of 0.537M NaOH solution = 28/1000*0.537 = 0.0150mol NaOH
This will react with 0.0150/2 = 0.0075 mol H2CO3
20mL of H2CO3 must contain 0.0075 mol H2CO3
1000mL of H2CO3 will contain : 1000/20*0.0075 = 0.0375mol H2CO3
Molarity of H2CO3 = 0.0375M
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.