Lead ions can be removed from solution by precipitation with sulfate ions. Suppo

Question

Lead ions can be removed from solution by precipitation with sulfate ions. Suppose that a solution contains lead(II) nitrate

Write complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

Write net ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

and complete the equation

NaOH(aq)+(NH4)2SO4(aq)?

Explanation / Answer

Lead (II) nitrate and sodium sulfate are both soluble, so they form aqueous solutions.

Molecular equation:
Pb(NO3)2 (aq) + K2SO4 (aq) -----> PbSO4 (s) + 2KNO3 (aq)
Total ionic:
Pb2+ (aq) + 2NO3- (aq) + 2K+ (aq) + SO42- (aq) -----> PbSO4 (s) + 2K+ (aq) + 2NO3- (aq)
Net ionic:
Pb2+ (aq) + SO42- (aq) -----> PbSO4 (s)

K+ and NO3- are spectator ions since NaNO3 is soluble.

Sodium sulphate and water

2NaOH + (NH4)2SO4 ---> Na2SO4 + 2NH3 + 2H2O

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