I2O5 + 5 CO -> I2 + 5 CO2 a- what mass of I2O5 is needed to react with 5 moles o

ID: 852913 • Letter: I

Question

I2O5 + 5 CO -> I2 + 5 CO2

a- what mass of I2O5 is needed to react with 5 moles of carbon monoxide ?

b-what mass of I2O5 is needed to react with 5 g of carbon monoxide react ?

c-what mass of carbon dioxide is produced when 10 moles of carbon monoxide react?

d-what mass of carbon dixide is produced when 25 g diiodine penoxide react?

e- how many moles of iodine are produced when 2.5 moles of carbon dioxide are produced?

f- how many grams of iodine are produced when 50 grams of carbon dioxide are produced ?

1 mole of I2O5 needed for production of 5 mole of CO2

mass of I2O5= moles * molar mass =1 mole*333.81 g.mole^-1=333.81g I2O5 is needed

b) number of moles of CO =5g/28g/mol = 0.179mole

1 mole of I2O5 needed for react with 5 mole of CO

the number of moles of I2O5 required to react with 0.179 moile CO is 0.0358mole of I2O5

mass of I2O5=moles of I2O5 *molr mss oF I2O5 = 0.0358*333.81=12.0g

5 moles of CO prodeces 220 g of CO2 so

10 moles of CO will produce 440 g of CO2

333.81g of I2O5 will produce 220g of CO2 so

25 g of I2O5 will produce 16.48g of CO2

when 5 mole of CO2 produced the number of moles of I2 = 1 so

the number of moles of I2 produced when 2.5 mole of CO2 produced will be 0.5 mole of I2

when 220 g of CO2 produced the grams of Iodine produced will be 253.8g so

the grms of I2 produced when 50 grmas of CO2 produced is 57.68g of I2

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