Given: Ksp(Ag2CrO4) = 1.2Ý10-12 Ksp(BaCrO4) = 2.1Ý10-10 For a solution which is

Question

Given: Ksp(Ag2CrO4) = 1.2Ý10-12 Ksp(BaCrO4) = 2.1Ý10-10 For a solution which is initially 0.090 M in Ba2+ and 0.090 M in Ag+, it is desired to precipitate one of these ions as its chromate (CrO42) salt to the maximum possible degree without precipitating any of the other cation. From this solution, which ion can be selectively first-precipitated by controlled addition of CrO42 and, ideally, what is the maximum possible percentage of that ion which can be exclusively so precipitated? (Assume that there is no change in the total volume of the solution.)

Explanation / Answer

Example #1: The Ksp for BaSO4 is 1.1 x 10

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