In oxidation-reduction reactions, one substance loses electrons (oxidation) whil

Question

In oxidation-reduction reactions, one substance loses electrons (oxidation) while another substance gains electrons (reduction). A convenient way to recognize oxidation is to look for an increase in charge. Similarly, a convenient way to recognize reduction is to look for a decrease in charge. Consider the following equation: 2MgO(s) rightarrow 2Mg(s) + O(g) Here is the same reaction, but with the ionic compound MgO rewritten to show its individual ions: 2Mg2+ + 202 rightarrow 2Mg(s) + O2(g) Now it is much clearer to see that magnesium decreases in charge (reduction) while oxygen increases in charge (oxidation). Which of the following reactions would be classified as oxidation-reduction? Check all that apply. 2Na(s) + Cl2 (g) rightarrow 2NaCl(s) Na(s) + CuCl(aq) rightarrow NaCl(aq) + Cu(s) NaCN(aq) + CuCl(aq) rightarrow NaCl(aq) + CuCN(s)

Explanation / Answer

1) Na can loose 1e- .........oxidation
   cl +1e- ....>Cl- ................reduction

2) Na can loose 1e- .........oxidation
    Cu+ can accept 1e- ..........reduction
so th first and second reactions are oxidation -reduction reactions

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