LON-CAPA Reakce x a Jeremih Feat. YG- Don\'t *GEd Sheeran Don\'t xY combustion a

Question

LON-CAPA Reakce x a Jeremih Feat. YG- Don't *GEd Sheeran Don't xY combustion analysis of x https://access4.on-capa. sedu/enc/92/e0a8 15e50ebdb7e7 9009b6b28aab f19o49b50940oo679d4a 11 Adarsh Singh (Student section: FQ5) CHEM 102F Fall 2014 Main Menii I contents Grades Course Contents Exam 2 Retake 10/26/14 11/02/14 Exam Retake Problem Combustion analysis of a 12.80 g of an unknown compound (containing c H and o) generated 22.51 g CO2, and 10,74 g H20 What is the empirical formula of this unknown compound? (Please place a 1 for for subscripts that are less than 2, i.e. CH20 should be c1H201) subma Answer Tries 0/3

Explanation / Answer

(22.51 g CO2) / (44.00964 g CO2/mol) x (1 mol C / 1 mol CO2) x (12.01078 g C/mol) = 6.14326 g C

(10.74 g H2O) / (18.01532 g H2O/mol) x (2 mol H / 1 mol H2O) x (1.007947 g H/mol) = 1.20179 g H

(12.8 g total) - 6.14326 g C - 1.20179 g H = 5.4549 g O

(6.14326 g C) / (12.01078 g C/mol) = 0.5114788 mol C
(1.20179 g H) / (1.007947 g H/mol) = 1.1923146 mol H
(5.4549 g O) / (15.99943 g O/mol) = 0.3409434 mol O
Divide by the smallest number of moles:
(0.5114788 mol C) / 0.3409434 mol = 1.500
(1.1923146 mol H) / 0.3409434 mol = 3.5
(0.3409434 mol O) / 0.3409434 mol = 1.00
Round to the nearest whole numbers to find the empirical formula:
C1.5H3.5O = C3H7O2

Empirical Formula = C3H7O2

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