I HAVE A COUPLE SIMPLE QUESTIONS I NEED HELP WITH. Please help :( 1.3 grams 5 de

Question

I HAVE A COUPLE SIMPLE QUESTIONS I NEED HELP WITH. Please help :(

1.3 grams

5 degree Celcius

1. FOR FIRST TABLE ONLY.

Calculate the approximate enthalpy of the reaction in joules. Show your work.

Estimate that 1.0 mL of vinegar has the same thermal mass as 1.0 mL of water. Ignore the thermal mass of the sodium bicarbonate. Note: it takes about 4.2 joules (J) to change 1.0 gram (1.0 mL) of water 1.0

TABLE 1 : enthalpy of baking soda and vinegar reaction Volume of vinegar 25mL Mass of sodium Bicarbonate(baking soda)

1.3 grams

Initial Temp of vinegar 23 degrees Celcius Final Temp of vinegar 18 degree Celcius Change in temperature

5 degree Celcius

Explanation / Answer

1. q = msDT
q = ?
m= mass of vonegar = 25 grams
S = specific heat = 4.2 j/g.c
DT = 23-18 = 5

q = 25*4.2*5 = 525 joule

Enthalpy of reaction DH = q = + 525 joule. It is endothermic reaction.

2.

*    Temperature in the reaction increases,
*    10 degree celcius temperature increases,
*    It is a exothermic reaction.
From the table when time goes on temperature gradually increases. so that its a exothermic and and finally reaches to 29 degree Celcius, There fore 10 Degree celcius temperature increases.

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