1) If 5.00 ml of a solution containing 4.00 x 10 -2 M iron is placed in a 100.0

Question

1) If 5.00 ml of a solution containing 4.00 x 10-2M iron is placed in a 100.0 ml volumetric flask and filled to themark with deionized water, what will be the concentration of ironin this new solution?

2) A 1.50 g sample of an iron containing compound wasdissolved in 100.0 ml of solution. A 2.00 ml portion of thissolution was placed in a 100 ml volumetric flask and diluted to themark with deionized water. The iron concentration of thisdilute solution was determined to be 1.112 x 10-3M. What percent of this compound is iron?

Explanation / Answer

1) M1V1=M2V2

4.00*10^-2*5=M2*100

M2=2*10^-3M

2)M= (W/V)%*10/M.W

1.112*10^-3= (W/V)*10/55.85

(W/V)%= 62.1%

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