procedure Determine the Molarity of HCl My data Measured Na 2 CO 3 into three fl

Question

procedure

Determine the Molarity of HCl

My data

Measured Na2CO3 into three flasks

Volume required for Titration  

Beaker/ Flask # 1: 46.4mL

Beaker/ Flask # 2: 46.7mL

Beaker/ Flask # 3: 46.5mL

Please help me i want to know the molarity of HCl. I don't know whether i should just find the moles of the carbonate and then just calculate molarity using the equation provied or use M1*V1= M2V2

Please help

Beaker/ Flask # 1 Beaker/ Flask # 2 Beaker/ Flask # 3 0.214g 0.216g 0.213g procedure Add about 4mL of concentrated HCl to 400mL of distilled water into a 500mL volumetric flask. Fill to the mark with distilled water. Mix thouroughly Weigh out 3 samples of dry Na2CO3 between 0.2-0.25 grams into thre 250mL flasks. dissolve each in 50mL of distilled water. Add 3 drops of methyl orange indicator to each solution and titrate with the HCl solution untill the solution begins to change from yellow to red. Boil solution for 2-3 minuites and cool to room temperature Complete the titration. Determine the Molarity of HCl My data Measured Na2CO3 into three flasks Beaker/ Flask # 1 Beaker/ Flask # 2 Beaker/ Flask # 3 0.214g 0.216g 0.213g Volume required for Titration Beaker/ Flask # 1: 46.4mL Beaker/ Flask # 2: 46.7mL Beaker/ Flask # 3: 46.5mL Please help me i want to know the molarity of HCl. I don't know whether i should just find the moles of the carbonate and then just calculate molarity using the equation provied or use M1*V1= M2V2 Please help

Explanation / Answer

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Standardization of a Hydrochloric Acid Solution by Titration of a Known Mass of Reactant

Suppose a chemistry problem requires you to "standardize" a hydrochloric acid (HCL) solution that has an approximate molarity (M) of 0.1.

Note that molarity is defined as the molar mass of a chemical substance per liter of solution.

Assume that the HCL solution was standardized by titration of 0.275 grams (g) of pure sodium carbonate, Na2CO3, to an end-point indicated at 48.5 milliliters (ml) of HCL.

Write the chemical equation of the reaction: Na2CO3 + 2HCL = 2NaCL + H2O + CO2.

Note that the molar ratio of the reaction is 2 moles of HCL / 1 mole of Na2CO3.

Calculate moles of Na2CO3 by dividing the mass of NaCO3 by its molar mass, as follows: 0.275 g NaCO3 / [106.0 g Na2CO3 / 1 mole Na2CO3] = 0.00259 moles Na2CO3.

Multiply moles of Na2CO3 by the molar ratio to find moles of HCL, as follows: 0.00259 moles Na2CO3 x [2 moles HCL / 1 mole Na2CO3] = 0.00518 moles HCL.

Calculate the concentration value, or molarity, of the HCL solution, as follows: 0.00518 moles HCL / [48.5 ml HCL x 1 liter / 1000 ml] = 0.107 M.

Read more : http://www.ehow.com/how_8745499_calculate-titration-value.html

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