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a) A sample of tris(hyroxymethyl)aminomethane (H2NC(CH2OH)3), which is a base, w

ID: 858137 • Letter: A

Question

a) A sample of tris(hyroxymethyl)aminomethane (H2NC(CH2OH)3), which is a base, with a mass of 0.6247 g is dissolved in water and used to standardize a solution of hydroiodic acid. An endpoint is reached when 23.89 mL of hydroiodic acid has been added. Determine the molarity (in mol/L) of the hydroiodic acid solution. Report your answer to four significant figures.

Please show your work, this is a practice question for an upcomming exam so I need to know the steps not the answer.

Thank you

Ps: If a thorough answer is given, I will award the answerer 600 points.

Explanation / Answer

Molecular weight of tris(hyroxymethyl)aminomethane is 121.14

therefore moles = mass / mol wt = 0.6247 = 0.0051 moles

volume of HI used = 23.89

at equivalent point moles of tris(hyroxymethyl)aminomethane = moles of acid = 0.0051

so moles of HI = 0.0051 moles

so molarity of HI = 0.0051 / 23.89 = 2.15 X 10-4 M