Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

ent 161) Assignment Gradebook FULL SCREEN PRINTER VERSION 4 BACK. NEXT Reaction

ID: 858343 • Letter: E

Question

ent 161) Assignment Gradebook FULL SCREEN PRINTER VERSION 4 BACK. NEXT Reaction Rates and Temperature TO4/S04 The reaction C2H5B C2H4, HBr, follows first-order kinetics and has an activation energy of 224 k mol 1. At 363 °C, k 0.0000100 s 1. Find the temperature (in °C) at which half-live will be 100 min? Round your answer to 3 significant figures The number of significant digits is set to 3; the tolerance is +/-2% Question Attempts: o of 1 used SAVE FOR LATER SUBMIT ANSWER Copyright o John Wiley & Sons, Inc. or related companies. All rights reserved 2000-2014 by

Explanation / Answer

by using the arrhenius equation , k = Ae-Ea/RT , where k = rate constant , T=temperature , Ea = activation energy , R=gas constant ,

for 2nd case , we know for a 1st order equation , half life = ln2 / k . so k = ln2 / 60*100 = 1.155*10-4

for 1st case , given , T =363+273 = 636K , k1= 0.00001 , so here , A=keEa/RT , so A = 2.5*1013

2nd case ,

T=? , so by applying th same equation , T = Ea /( R[lnA-lnk]) , so T= (224000) / (8.314*[42.36+8.772])

so T = 526.92 K