will someone solve these problems for me \"Homework part 2 for monday\", please.
ID: 85902 • Letter: W
Question
will someone solve these problems for me "Homework part 2 for monday", please. Thank you
For rhodopsin, researchers observed absorbance recovery of a 6 mu m distance after 23 s. From the data they calculated diffusion rate of the protein: in two dimensions the Diffusion constant D = l^2/4T where l = the distance and T is the time. What is the diffusion constant for rhodopsin in cm^2/s? Homework Part 2 for Monday: How long would it take rhodopsin to travel 10 mu m? (the length of a typical cell) How long (in hours) would it take rhodopsin to travel 100 mu m? (the length of a large cell like an egg)Explanation / Answer
from the given data, diffusion constant = 9/23
Answer 2. if l= 10 then T=?
D= l2/4T, 9/23=100/4T,
T=(25 x 23)/9= 63.88 s
thus, it will take around 63.88~ 64 seconds to travel across a 10 micrometer cell
Answer 3. D=9/23, l=100 by applying the formula,
9/23= (100)2/4T
T= (2500 x 23)/9= 6388.88 seconds
time in hours= 6388.88/3600= 1.77 hours [ 1 hour= 60 min, 1 min = 60 s i.e. 1 hour =60 x 60=3600 s]
it will take around 1.77 ~2 hours to travel 100 micrometer
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