Which of following is true knockout mice a) They can be sometimes be used as mod

Question

Which of following is true knockout mice a) They can be sometimes be used as model systems for disease b)One step in their formation is the injection into early embryo (blastocyst) c) One step in their formation.... d) All the above Which of the following is FALSE about the product antibody diversity? a) There is multiple V, D, and J regions b) Recombination of gene segments occur in the lymphocytes c) All variation is produced by alternative splicing d) There is hypermutability of the V regions The traits shown in this pedigree are generally a) Dominant b) Recessive The trait is generally a) X-linked b) autosomal A genotype of 100 individuals were data to 40 AA 20 Aa 40 aa. Calculate frequencies of the A and a allele in this population. Include the heterozygous in your computations. Is the population in equilibrium? Why? Why not?

Explanation / Answer

Answer

Frequency of genotype, AA =(p^2) = 40/100 = 0.4

The frequency of allele, A= (p)=Sqrt of 0.4 = 0.63

Frequency of genotype, aa =(q^2)= 40/100 = 0.4

The frequency of allele, a= (q)= Sqrt of 0.4 = 0.63

According to hardy-weinberg law, p+q=1

But p+q= 0.63+0.63=1.26

Expectrd Heterozygous genotype frequency = 2*p*q = 2*0.63*0.63= 0.79

The observed heterozygous genotype frequency= 20/100 = 0.2

p^2+2pq+q^2= 1

0.4+0.79+0.4= 1.59

The expected and observed heterozygous genotype frequency is not similar. So that the population is not in equilibrium.

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