Value Map Organic Chemistry Roberts & Company Publishers presented by Sapling Le

Question

Value Map Organic Chemistry Roberts & Company Publishers presented by Sapling Leaming Marc Loudon A reaction has a standard free-energy change of -3.14 kJ/mol at 25 oC. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively? Number Number Number Al- M M M How would your answers above change if the reaction had a standard free-energy change of +3.14 kJ/mol? O There would be no change to the answers O There would be less A and B but more C There would be more A and B but less C. O All concentrations would be lower O All concentrations would be higher.

Explanation / Answer

G=-RT*ln(k)

or 3.14*10^3=8.31*298*ln(k)

or k=3.55

let the dissociation be x.so,

3.22=x/((0.3-x)*(0.4-x))

or x=0.137

so [C]=0.137

[A]=0.163

[B]=0.263

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