The quantity or antimony in a sample can be determined by an oxidation-reduction

Question

The quantity or antimony in a sample can be determined by an oxidation-reduction titration with an oxidizing agent. A 6.99-g sample of stibnite, an ore of antimony, is dissolved in hot, concentrated HCI(aq) and passed over a reducing agent so that all the antimony is in the form Sb3^+(aq), The Sb^+3(aq) is completely oxidized by 37.8 mL of a 0.105 M aqueous solution or KBrO3(aq). The unbalanced equation for the reaction is BrO3, (aq) + Sb^3+ (aq) right arrow Br (aq) + Sb^5 + (aq) (unbalanced) Calculate the amount of antimony in the sample and its percentage in the ore.

Explanation / Answer

my answer is 2.3 g and 12.6 %

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