Molly needs to make 1 liter of a 1.5 M glucose solution for use in an experiment

Question

Molly needs to make 1 liter of a 1.5 M glucose solution for use in an experiment. The molar mass of glucose is 180.16 g/mol.

(a) What is the solute in the resulting solution? What is the solvent in the resulting solution? How do you know? (5 points)
(b) Is this solution a strong electrolyte, a weak electrolyte, or a nonelectrolyte? Why? (5 points)
(c) How many grams of glucose are required to make 1 L of a 1.5 M glucose solution? Be sure to show your work for full credit. (8 points)
(d) What volume (mL) of a 0.30 M glucose solution can be prepared by diluting 100 mL of a 1.5M glucose solution? Be sure to show your work for full credit.

Explanation / Answer

a.

In this case the solute is glucose

and the solvent is water

In any solution the substance which is present in small quantity is solute and the substance which is present in large quantity is solvent.

here also (from answer c) it clear that glucose is 270.24 g and water is 1 litre or 1000 mL (1000x0.998=998 g)

b.

Glucose in water forms a non-electrolyte solution since glucose doesnt give any ions in the solution

c.

We know that the molarity is given as M=(no. of moles of solute)/Volume in L

and no. of moles = weight/ molecular weight

therefore amount of glucose w = 1.5 x 180.16 = 270.24 g

d.

Law of dilution is M1V1=M2V2

therefore the volume V2= (0.100 x 1.5) / 0.3

= 0.500 L or 500 mL

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