Hadley needs to make a 10% (m/v) NaCl solution for use in an experiment. (a) Wha

Question

Hadley needs to make a 10% (m/v) NaCl solution for use in an experiment.

(a) What is the solute in the resulting solution? What is the solvent in the solution? How do you know?
(b) Is this solution a strong electrolyte, a weak electrolyte, or a nonelectrolyte? Why?
(c) How many grams of NaCl are required to make 250 mL of the 10% (m/v) NaCl solution? Be sure to show your work for full credit.
(d) What volume (mL) of a 2% (m/v) NaCl solution can be prepared by diluting 100 mL of a 10% (m/v) NaCl solution? Be sure to show your work for full credit.

Explanation / Answer

a) The solute is NaCl and the solvent is water. This you know from the solubility chart.

b) Yes, it is a strong electrolyte, as it dissociates completely into ions (Na+ and Cl-) upon dissolution.

c) 10% m/v NaCl solution means that 100 mL of solvent has 10 g of solute in it

So, 250 mL of solvent will require (10 / 100) x 250 g of solute = 25 g solute or NaCl

d) C1V1 = C2V2

Here, C1 = 10% m/v, V1 = 100 mL, C2 = 2% m/v, V2 = ?

So, 10 x 100 = 2 x V2

or V2 = 1000 / 2 = 500 mL

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