pint NCakulator Periodic Table Grad Question 3 or 10 Inaprroct Incorrect K Incor

Question

pint NCakulator Periodic Table Grad Question 3 or 10 Inaprroct Incorrect K Incorrect 1ncorrect saplingileaming Find the conditional formation constant for Ba(EDTAY at pH9.00, where log Kr is 7.88 and cer4 is 0.041. Number K 3.075x 10 Find the concentration of free Ba in 0.065 M NazlBa(EDTA) at pH9.00. Incorrect. You have correctly found the conditional formation Number constant for Ba (EDTA) (KY 3100000). To find the concentration Ba 6.52 x 10 M of Ba make an equilibrium table for the complex formation. Ba EDTA Bay Initial Concentration (M) 0.065 Final Concentration (M) 0,065 Set the equilibrium expression equal to Kr, and solve for x. Previous & Give Up & View Solution Try Again 0 Next HExu Avalable Due Dat Points Grade Pollde You c You You you

Explanation / Answer

We have Kf1 = 3.075 x 106

If we set the equilibrium expression equal to Kf1

Then we will have

                          Kf1    = [BaY2- ] / [Ba2+][EDTA]

                   3.075 x 106   = (0.065-X) / X2

                   X2     =   2.11 x 10-8   - (X/3.075) x 10-6

                X2 + 3.25 x 10-7 X = 2.11 x 10-8

              if we solve the above equation for X we will get

         X = 0.000145 M

            = 1.45 x 10-4 M

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.