1. 25.00 mL of a 0.0060 M solution of sodium hydroxide was titrated with 0.010 M

Question

1. 25.00 mL of a 0.0060 M solution of sodium hydroxide was titrated with 0.010 M hydrochloric acid using methyl red indicator.
a. Calculate the volume of HCl at equivalence point.
b. Draw a rough sketch of the titration curve (pH vs VH+ ). Hint: find the initial pH and pH at equivalence point and pH at V=2Veq.
c. Calculate ?pH and show the transition pH of the indicator on the pH-curve.
d. Calculate Vf and show Vf and Ve.q. on the pH curve. Calculate the indicator error.
Methyl red: Red 4.66.2 Yellow

Explanation / Answer

Answer: According to question

HCL + NaOH ----------------> NaCl + H2O

It is a 1:1 ratio

Now we have to use M1V1 = M2V2

0.025 L * 0.0060 = 0.010 * v2

V2 = 0.015 L

means the volume of HCl at end point is 15 ml .

Note : use the Ph metery and note the variation of Ph with respect to volume and take 10 to 12 readings and then draw the graph it is a experimental work .

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