You used 1.0014g of p-aminobenzoic acid and 3mL of ethanol (along with other rea

ID: 868090 • Letter: Y

Question

You used 1.0014g of p-aminobenzoic acid and 3mL of ethanol (along with other reagents, not important in this case) to make bezocaine.

Answer the following questions, show all calculations.

what is the molar mass(g/mol), mass and moles of P-aminobenzoic?

what is the molar mass(g/mol), mass and moles of ethanol?

What is the limiting reagent? Theoritical yield of benzocaine?

Hint: molar mass can be obtained via a credible internet source. Use that to help you do some of the calculations.

Given an IR Spectrum of benzocaine, what will be the significant peaks and their assignments?

Mass of p-amino benzoic acid = 1.0014 g

Molar mass of p-amino benzoic acid = 137.14 g/mol

Moles of p-amino benzoic acid = Mass / Molar mass = 1.0014 / 137.14 = 7.30 x 10^-3 mol = 0.00730

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Volume of ethanol = 3 mL

Density of ethanol = 0.789 g/mL

Mass of ethanol = 2.367 g

Molar mass of ethanol = 46.1 g/mol

Moles of ethanol = Mass / Molar mass = 2.367 / 46.1 = 0.0513 mol

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As the moles of p-amino benzoic acid are less than the moles of ethanol, p-amino benzoic acid is the limiting reagent.

Thus, 0.00730 mol of p-amino benzoic acid gives 0.00730 mol of benzocaine.

Mass of benzocaine = Moles of benzocaine x Molar mass of benzocaine

= 0.00730 mol x 165.2 g/mol = 1.20 g of benzocaine.

Theoretical yield of benzocaine = 1.20 g

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Useful frequencies in the IR spectrum are:

3410 cm-1 N

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