Please solve this equilibrium constant question step by step Hydrogen and carbon

Question

Please solve this equilibrium constant question step by step

Hydrogen and carbon dioxide react at a high temperature to give water and carbon monoxide. H2(g) + CO2(g) H2O(g) + CO(g) Laboratory measurements at 986 *C show that there are 0.11 mol each of CO and H2O vapor and 0.087 mol each of H2 and CO2 at equilibrium in a 50.0-L container. Calculate the equilibrium constant for the reaction at 986 degree C. Suppose 0.010 mol each of H2 and CO2 are placed in a 200.0-L container. When equilibrium is achieved at 986 degree C, what amounts of CO(g) and H2O(g), in moles, would be present? [Use the value of K from part (a).]

Explanation / Answer

H2           +    CO2        =       H2O      +    CO

0.087 mol

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.