Homework, please help! 1. (23 pIs) Consider the following voltaic cell: (a) In w

Question

Homework, please help!

1. (23 pIs) Consider the following voltaic cell: (a) In which direction do electrons flow in the external circuit? (b) In which half-cell does reduction occur? (c) In which half-cell do electrons leave the cell? (d) Calculate E^0 cell in volts. (e) Which electrode is the negative pole? (f) Which electrode decreases in mass during cell operation? (g) Suggest a solution for the cathode electrolyte. (h) Suggest a pair of ions for the salt bridge. (i) For which electrode could you use an inactive material? j) To which beaker do anions within the salt bridge move to maintain charge neutrality? (k) Write balanced reduction and oxidation half reactions and a balanced overall cell reaction. Reduction:

Explanation / Answer

note : in your image right hand side picture is not clearly visible. i thought it is Ag electrode. based on that i solved total probelm . if it is Ag no problem . other than Ag answers d, g, k changes. any clarification you can ask me

a) Electrons flow from left to right

b) at right hand side half -cell reduction occur

c) at left hand cell electrons leaves the cell

d)

E0cell= E0cathode- E0anode

E0cell= E0Ag+/Ag- E0Fe+2/Fe

          = 0.80 - (-0.44)

         = 1.24V

e) Fe electrode is negative pole (at left hand side)

f) Fe electrode decreases its mass because of oxidation and converts into ions

Fe (s)---------------------> Fe+2(aq) +2e-

g) AgNO3 or Ag2SO4

h) K+ and Cl-   (salt KCl)

i) for cathode we use inert material

j) left hand beaker anions moves towards salt bridge

k)  

reduction : 2Ag+(aq) + 2e- -----------------------> Ag(s)

oxidation:   Fe(s) ---------------------------> Fe+2(aq) +2e-

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overall : 2Ag+(aq) + Fe(s) ---------------->Fe+2(aq) + Ag(s)

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