If it takes the same amount of heat to increase the temparature of 50.0 g of a m

Question

If it takes the same amount of heat to increase the temparature of 50.0 g of a mineral by 20 degrees C as it does to increase the temparature of 100.0 g of metal by 10.0 degree C , the spacific heat capacity of the mineral is A 10.0 g metallic sample is heated to 80.00 degree C and placed into 30.0 g of H2O at 25.00 degree C in a calorimeter producing a final temperature of 26.65 degree C. What is the identity of the metal? What is the enthalpy change for the reaction of nitrogen and oxygen to form nitrogen dioxide? Which equation describes the standard enthalpy of formation of CH4(g)? What is Delta H degree (in kJ) for the reaction below using the data given?

Explanation / Answer

32.

Mass.mineral x sp.heat.min x dt = Mass.metal x sp.heat.met x dtemp =

50 x sp.heat.min x 20 = 100 x sp.heat.met x 10 =

Sp. heat mineral/sp. heat metal = 100x 10/ (50x20) = 1

Answer D.

33. Use calorimetric equation

10g x cx x (80-26.65) = 30 g x 4.18 x (26.65-25)

10g x cx x (80-26.65) = 30 g x 4.18 x (26.65-25)

533.5 cx = 206.91

Cx = 0.388

Answer B copper

34

180

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