The following is an oxidation-reduction reaction: CH 4 (g) + O 2 (g) ? CO 2 (g)
ID: 873754 • Letter: T
Question
The following is an oxidation-reduction reaction: CH4(g) + O2(g) ? CO2(g) + H2O(g)
True
False
What is the oxidizing agent in the following reaction? H2C2O4(aq) + 2KMnO4(aq) + 6HCl ? 2MnCl2(aq) + 2KCl(aq) + 10CO2(g) + 8H2O(l)
What species is undergoing reduction in the following reaction? NO3-(aq) + 4Zn(s) + 7OH-(aq) + 6H2O(l) ? 4Zn(OH)42-(aq) + NH3(aq)
What is the concentration (in M) of a sodium chloride(NaCl) solution prepared by dissolving 17.4 g of NaCl (58.44 g/mol) in enough water to produce 472 mL of solution? (Be careful not to drop significant digits.)
What mass of copper (II) acetate (Cu(C2H3O2)2 141.64 g/mol) is required to produce 500.0 mL of a 1.23M solution of copper(II) acetate?
What is the concentration of an HCl solution if 108.7 mL of it reacts completely with 29.6 g of Na2CO3 (105.99 g/mol)?
Na2CO3 (s) + 2 HCl(aq) ? 2 NaCl(aq) + H2O(l) + CO2(g)
What volume (in mL!!!) of 1.67 M NaOH is required to react with 29.2 mL of 1.44 M citric acid according to the following reaction?
H3C6H5O7 (aq) + 3NaOH (aq) ? 3H2O(l) + Na3C6H5O7 (aq)
Explanation / Answer
The following is an oxidation-reduction reaction: CH4(g) + O2(g) ? CO2(g) + H2O(g)
True
Yes, that is a redox reaction. Carbon goes from a -4 state to a +4 state (oxidized). Oxygen goes from a 0 state to a -2 state (reduced).
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What is the oxidizing agent in the following reaction? H2C2O4(aq) + 2KMnO4(aq) + 6HCl ? 2MnCl2(aq) + 2KCl(aq) + 10CO2(g) + 8H2O(l)
Balancing does not matter for O.N. It is quoted for 1 atom.
H2C2O4 H +1 O -2 C +3
KMnO4 K +1 Mn +7 O -2
HCl H +1 Cl -1
CO2 C +4 O -2
MnCl2 Mn +2 Cl -1
KCl K +1 Cl -1
H2O H +1 O -2
If O.N increases the that molecule is getting oxidised and hence is a red. agent and vice-versa.
Here KMnO4 is getting reduced (+7 to +2)and is ox.agent.
H2C2O4 is getting oxidised (+3 to +4)and is red. agent.
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What species is undergoing reduction in the following reaction?
NO3-(aq) + 4Zn(s) + 7OH-(aq) + 6H2O(l) ? 4Zn(OH)42-(aq) + NH3(aq)
Look at the oxidation state of N on the left side, it's +5. Now look at the oxidation state of N on the right side of the equation, it's +3.
N went from +5 to +3, that means it was REDUCED, therefore it is the OXIDIZING agent.
Zn on the left side of the equation is 0, on the right side it's +2.
Zn went from 0 to +2, the number went up.
This means that Zn was OXIDIZED, therefore it is the REDUCING agent.
If the number goes down, it is reduced, and is the oxidizing agent.
If the number goes up, it is oxidized, and is the reducing agent.
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