6. Isotopes of a given element have the same number of , but different numbers o

Question

6. Isotopes of a given element have the same number of , but different numbers of in their nucleus. a. neutrons, electrons b. electrons, protons c. protons, electrons d. protons, neutrons 7. All of the following statements are true EXCEPT a. for any neutral element, the number of protons and electrons are equal. b. electrons and protons have equal mass, but opposite charges c. the mass number is the sum of the number of protons and neutrons. d. the atomic number equals the number of protons. 8. Which two of the following atoms are isotopes? 23 23 9. Which of the following particles will not be deflected by charged plates? particles b, particles c.a particles d. protons 10. An element consists of two isotopes. The abundance of one isotope is 95.72% and its atomic mass is 114.9041 u. The atomic mass of the second isotope is 112.9043 u. What is the average atomic mass of the element? a. 113.9 u b. 113.0 u c. 113.9 u d. 114.8 u

Explanation / Answer

6) Isotopes of the same element have the same number of PROTONS but different number of NEUTRONS.

7) Statement A is CORRECT since a neutral atom consists of equal number of electrons and protons (equal number of plus and minus charge cancels out and the atom becomes neutral)

Statement B is INCORRECT since the mass of an electron is 9.1093897*10-31 kg whereas that of a proton is 1.6726231*10-27 kg

Statement C is CORRECT since mass number is defined in that way

Statement D is CORRECT

8) Isotopes of a given element have the same number of protons in each atom.

Hence B) is the correct answer. Isotopes of Titanium (Ti)

9) A) Gamma Particles are not deflected by charged plates. This is because Gamma rays are highly energetic waves with no charge associated with them. B) Beta particles ate negatively charged hence they are attracted to the positively charged plate. c) Alpha particles are positively charged hence they are attracted to the negatively charged plate.

10) Mass of Isotope 1 = 114.9041 u

% of Isotope 1 = 95.72

Mass of Isotope 2 = 112.9043 u

% of Isotope 2 = 100 - 95.72 = 4.28

Average mass = 114.9041 x 0.9572 + 112.9043 x 0.0428 = 109.9862 + 4.8323 = 114.8185 = 114.8 (approx.)

Hence the answer is D) 114.8 u

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