a steel tank contains .500 moles of N2 at STP What is the final pressure in the

Question

a steel tank contains .500 moles of N2 at STP What is the final pressure in the flask if an additional 2.00 g of N2 has is added to the flask and the flask is cooled to -55C a steel tank contains .500 moles of N2 at STP What is the final pressure in the flask if an additional 2.00 g of N2 has is added to the flask and the flask is cooled to -55C a steel tank contains .500 moles of N2 at STP What is the final pressure in the flask if an additional 2.00 g of N2 has is added to the flask and the flask is cooled to -55C

Explanation / Answer

The Final pressure is sum of partial presure

=(n1+n2)RT

=(.5+.0714) X .08025 X328.15

=15.04 atm

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