For example one procedure could use a 100.00 mL (V2) volumetric flask and a 10.0

Question

For example one procedure could use a 100.00 mL (V2) volumetric flask and a 10.00 mL (V1) volumetric pipet or pipettor to prepare a 0.500 M (M2) solution of HCl. A 10.00 mL volumetric pipet or pipettor is used to transfer 5.00 M HCl (M1) to a 100.00 mL (V2) volumetric flask and then the flask is filled exactly to 100.00 mL with distilled water and mixed well. The same dilution can be done using 5.00 mL (V1) and a 50.00 mL (V2) volumetric flask if less solution is needed. One way to make different concentrations of HCl (M2) in a 100.00 mL (V2) volumetric flask from a stock 5.00 M (M1) solution would be to use different volumetric pipets. What would be the molarity (M2) of the 100.00 mL (V2) of dilute HCl if you used a 45.00 (V1) mL volumetric pipet?

Explanation / Answer

Volume of flask V2 = 100mL

Volume of pipet V1 = 1mL

Molarity of HCl M1 = 5M

Molarity of solution M2 = 0.50M

We have,

M2 = M1*V1/ V2

For new procedure,

V2 = 100mL

V1 = 45mL

M1 = 5M

Putting these values in above expression -

M2 = 5*45/ 100

Molarity of solution, M2 = 2.25M

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