10. Select the appropriate rate law for the substitution reaction between an alk
ID: 875398 • Letter: 1
Question
10. Select the appropriate rate law for the substitution reaction between an alkyl halide [RX], and hydroxide [OH] given the following observed relative rates in experiments a-c Experiment # RX] 0.02M 0.02M 0.04M 0.02M 0.02M 0.06M [OH]- Obs. Rel. Rate - 2 a) Rate- k[RX] b) Rate-k[RX][OH] c) Rate- k[RX]?[OH] d) Rate- k[OH]3 11. The order of a reaction (e.g., as in Sn1 or SN2, El or E2) tells a) how many of each reactant is involved in the rate-determining step of the reaction b) which reactants appear in the overall equation c) the neatness with which one can carry out the reaction d) the change in energy (AG) occurring during the reactionExplanation / Answer
10) let the rate law be
rate = k [RX]^x [OH-]^y
x and y are the orders
now
consider experiment a and c
we get
[RX] = constant
so
rate c / rate a = ([OH-]c/ [OH-]b)^y
so
3/1 = ( 0.06/0.02)^y
y = 1
now
consider experiment a and b
we get
[OH-] = constant
so
rate b / rate a = ( [RX]b / [RX]a)^x
2/1 = ( 0.04/0.02)^x
x= 1
so
the rate law is
rate = k [RX] [OH-]
so
the answer is option b) rate = k [RX] [OH-]
11) the order of reaction tells how many of each reactant is involved in the rate determining step
so the answer is option a
12)
we know that
nuclephile is the one which can donate a pair of electrons
electrophile is the one which can accept a pair of electrons
now
H30+ is an electrophile as it cannot accept further electrons
I-, ethylene is a nulcleophile as it can donate it paris of electrons but cannot accept electrons
ch3Oh can act as both because of the polarity of C-O bond
so
the answer it option B) Methanol , CH3OH
13)
the SN1 reaction does not depend much on the strength of the nucleophile
so
option d is true
the rate depends on the nature of the halide leaving group
so option b is true
the reaction if favoured by polar protic solvent
so the option c is ture
now
Sn1 reactions have a first-order dependence on the substate and zero-order dependence on nucleophile
so the option a is wrong
so
the answer is option a
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