Just do part 1 please. Please show all your work. 1. An aqueous solution of hydr

Question

Just do part 1 please. Please show all your work.

1. An aqueous solution of hydrochloric acid (HCI, molar mass = 36.5 g/mol) has a density of 1.18 g/mL and is 37 % HCI by mass. The solvent is water (molar mass = 18.0 g/mol). Perform the calculations indicated below. A) the molality of HC1 B) the mole fractions of HCl and water C) the molarity of HCI 2. Do the reverse calculations for the previous problems by using your answers for each part. A) mass percent from molality of HCI B) mass percent from the mole fractions of HCI and water C) mass percent from the molarity of HCI

Explanation / Answer

density= 1.18g/ml , mass = 37g

density = mass/volume => volume= mass/density= 37/ 1.18=31.3559ml= 31.3559x10^-3L

mole of HCl= 37/36.5= 1.013698

C--molarity= mole of solute / volume of solution in liter

molarity of HCl = 1.013698 / 31.3559x10^-3 = 31.89M

A---molality = m = mole of solute / Kg of solvent

m of HCl = 1.013698 / 63x10^-3kg = 16.09m

B--mole fraction = mole of HCl / mole of H2O

mole of H2O = 63/18= 3.5

mole fraction = 1.013698 / 3.5= 0.2896

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