For numbers 10-12 consider the reaciton of (CH3)3CCl in basic solution. (CH3)3CC

Question

For numbers 10-12 consider the reaciton of (CH3)3CCl in basic solution. (CH3)3CCl +OH- --> (CH3)3COH +Cl-

The accepted mechanism for this reaction is as follows:

Step 1 (slow)
(CH3)3CCl --> (CH3)3C+ + Cl-

Step 2 (fast)
(CH3)3C+ +OH- --> (CH3)3COH

10. Based on this mechanism, the rate determining step and the reaction intermediate respectively are?

A. Step 1 and (CH3)3COH
B. Step 2 and (CH3)3COH
C. Step 1 and (CH3)3C+
D. Step 2 and (CH3)3C+

11. What is the molecularity of step 1 of the mechanism and why?

A. Unimolecular
B. Bimolecular
C. Termolecular
D. Equimolecular

12. Based on this mechanism, the rate law for this reaction is?

A. rate=k[(CH3)3CCl]
B. rate=k[(CH3)3CCl][OH-]
C. rate=k[(CH3)3C+][OH-]
D. rate=k[(CH3)3C+][Cl-]

Explanation / Answer

10) The speed or the rate determining step of the reaction is determined by the slow reaction, since it will take larger time to complete the reaction in order to form the products

Hence the rate determining step is Step 1(being a slow reaction) and reaction intermediates are (CH3)3C+

which will gradually react with OH- to form an alcohol

Correct answer is option C

11) The reaction is unimolecular since only one of them will be deciding the rate of reaction

12) The order of this reaction will be 1, which is determined by the slow step

Hence correct answer will be option A

rate=k[(CH3)3CCl]

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