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Trial 1 Trial 2 Average Mass of Crushed Antacid (g) 0.5 0.5 0.5 Concentration of

ID: 877115 • Letter: T

Question

Trial 1

Trial 2

Average

Mass of Crushed Antacid (g)

0.5

0.5

0.5

Concentration of HCl (M)

1M

1M

1M

Volume HCl (mL)

10 mL

10 mL

10 mL

Concentration of NaOH (M)

1M

1M

1M

Initial NaOH Volume (mL)

10 mL

10 mL

Final NaOH Volume (mL)

5 mL

5 mL

Total Volume of NaOH Used (mL)

5 mL

5 mL

5 mL

Data Table 2. Experimental Results.

HCl available for neutralization (g)

0.3646 (g)

Moles of NaOH required to reach stoichiometric point

0.05 mols

Grams of HCl neutralized by antacid

1.4584 (g)

Grams of HCl neutralized per gram of antacid

2.9168 (g)

A.    If a TUMS® antacid tablet weighed 1.6 grams, how many moles of gastric acid (HCl) would it neutralize? Use the results obtained in Data Tables 1 and 2 to explain and quantify your answer.

B.    If you performed this experiment with a titrant of 0.5M NaOH, would you expect your results in Data Table 2 to change or stay the same? Explain your answer.

C.     The reaction that occurred when the TUMS® antacid mixed with the HCl resulted in an additional product (besides a salt and water). Did you see evidence of this product? Describe the experimental evidence you witnessed that supports the formation of the additional product.

Trial 1

Trial 2

Average

Mass of Crushed Antacid (g)

0.5

0.5

0.5

Concentration of HCl (M)

1M

1M

1M

Volume HCl (mL)

10 mL

10 mL

10 mL

Concentration of NaOH (M)

1M

1M

1M

Initial NaOH Volume (mL)

10 mL

10 mL

Final NaOH Volume (mL)

5 mL

5 mL

Total Volume of NaOH Used (mL)

5 mL

5 mL

5 mL

Explanation / Answer

From the given data tables -

a) The amount of HCl required per gram of antacid = 2.9168 g HCl / each gram of antacid

We have initially 1.6 grams of antacid, hence, the amount of HCl required

                          = (2.9168 g HCl/ each gram of antacid)(1.6 g antacid) = 4.666 g HCl

b) No, the results can't change by changing the concentration of NaOH. Because we used NaOH for back titration which depeds on the amount of HCl remained in the sample. Hence results may not change except NaOH consumption.

c) It can be predicted by considering the amount of HCl. If the amount of HCl consumed in the reaction is more than expected. It gives the experimental proof of the formation of additional product.

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