Determine ?H (kJ/mol) and?S (J/mol-K) for borax from the plot’s equation Ksp= 4

Question

Determine ?H (kJ/mol) and?S (J/mol-K) for borax from the plot’s equation

Ksp=

4 [B4O5(OH)4 2- ]³

-1.8061

can someone show how to calculate ?H (kJ/mol) and?S (J/mol-K)

T(K) 1/T(K-1) [borate ion]  B4O5(OH)4²¯

Ksp=

4 [B4O5(OH)4 2- ]³

ln Ksp 335.65 0.0029793 1.0685M 4.8796 1.5851 328.65 0.0030428 1.040M 4.4995 1.5039 323.65 0.0030898 0.7625M 1.7733 0.5728 317.65 0.0031481 0.445M 0.3525 -1.0427 313.15 0.0031934 0.345M 0.1643

-1.8061

our group Trendline for Data series 1 2-0.919 -1 -2 0.00288 0.00298 0.00308 0.00318 0.00328 1/T(K-1)

Explanation / Answer

We will use the two negative values and will get delta H and delta S. You can choose any set of two values.

deltaGo = -RT lnKsp

delta Go = -8.314 x 317.65 x -1.0427 = 2753.71 J (1)

delta Go = -8.314 x 313.15 x -1.8061 = 4702.23 J (2)

Also, delta Go = deltaHo - TdeltaSo

2753.71 =deltaHo - 317.65 deltaSo

4702.23 =deltaHo - 313.15 deltaSo  

solve system of equations and you will get

deltaHo = 140.29 KJ and deltaSo =432.98 J/K

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