Which of these options is true/correct? H IIF ] HF] G=-RT ln K =-(8.3 145 JK.mol

Question

Which of these options is true/correct?

H IIF ] HF] G=-RT ln K =-(8.3 145 JK.molX298 K) n(7.2 × 10-4 ) = 1.8 × 104 J/mol The concentrations are all at standard conditions, so G = G = 1.8 x 104 J/mol (Q = 1.0 and In Q = 0). Because Go is positive, the reaction shifts left to reach equilibriunm. a. G = 1.8 x 104 J/mol + (8.3 145 JK.mol)(298 K) ln G= 1.8 x 104 Jhnol-1.8 x 104 J/mol :0 (2.7 x 10%) 0.98 b. G = 0, so the reaction is at equilibrium (no shift). G-1.8 x 104 Jhnol + 8.3 145(298 K) G = 1.8×104 + 8.3 145(298) ln72x G_ 1.8 x 104+8.3 145(298) In In (1.0×10")-=-1.1 x 104 J/mol, shifts n ha00--1.1x1oninot shifts nght c. 1.0×10-5 lotom 0.27 7.2 × 10 (027) =1.8x104-1.8 x 10-0; d. +8.3145(298) n 72 x 10(0.27) at equilibriunm 1.0x10-3(067) = 2x 103 J/mol, shifts left e. 0 52

Explanation / Answer

The solution to the problem is as given below.

a. True

b. False

c. True

d. True

e. True

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