The atmosphere slowly oxidizes hydrocarbons in a number of steps that eventually

Question

The atmosphere slowly oxidizes hydrocarbons in a number of steps that eventually convert the hydrocarbon into carbon dioxide and water. The overall reactions of a number of such steps for methane gas is as follows CH4 (g) 502 (g) 5NO (g) CO2 (g) H2O(g) 5NO2(g) 2 OH(g Suppose that an atmospheric chemist combines 165 mL of methane at STP, 855 mL of oxygen at STP, and 58.5 mL of NO at STP in a 2.2 L flask. The reaction is allowed to stand for several weeks at 275 K. Part A If the reaction reaches 90.0% of completion (90 of the limiting reactant is consumed), what are the partial pressures of each of the reactants in the flask at 275 K? Enter your answers numerically separated by commas. CH41 oa, PNo atm Submit My Answers Give Up Part B If the reaction reaches 90.0% of completion (90.0% of the limiting reactant is consumed), what are the partial pressures of each of the products in the flask at 275 K? Enter your answers numerically separated by commas. coa, PH20, O2, OH atm Submit My Answers Give Up Part C What is the total pressure in the flask? atm Submit My Answers Give Up

Explanation / Answer

The solution is as shown below.

Use the relation,

Vg/Vt = Pg/Pt

pCH4 = nRT/V = 1 x 0.0831 x 275/0.165 = 138.5

pO2 = 1 x 0.0831 x 275/0.855 = 26.73

pNO = 1 x 0.0831 x 275/0.0585 = 390.64

Ptotal = 138.5 + 26.73 + 390.64 = 555.87

partial pressure component of CH4 = 138.5/555.87 = 0.25 atm

partial pressure component of O2 = 26.73/555.87 = 0.05 atm

partial pressure component of NO = 390.64/555.87 = 0.70 atm

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.