Ea = 4906 (this is what I calculated) For the rection studied 2I- + S2O8^-2 ----

Question

Ea = 4906 (this is what I calculated)

For the rection studied

2I- + S2O8^-2 -------> I2 + 2 SO4^-2

change in E rxn = change in H rxn = -322 kJ

A. Use this value and your experimental activation energy value to draw an energy profile for the reaction with the energies appropriately scaled on the vertical axis

B. Lable change in E rxn (change in H rxn) and Ea on the graph

C. Calculate Ea for the reverse reaction

graph has y axis = E and X axis = reaction progress

thank you will rate!

rxn Time (t)(sec) Rate (M/sec) k(M-1sec-1) ln k Temp (T)(K) 1/T (K-1) 1 35.90 2.78e-5 0.0087 -4.74 293.02 0.0034 6 27.60 3.62e-5 0.0056 -5.18 318.30 0.0031 7 29.23 3.42e-5 0.11 -4.55 302.01 0.0033 8 71.05 1.40e-5 0.004 -5.52 274.20 0.0036

Explanation / Answer

The energy profile diagram is shown below.

Activation energy for reverse reaction = activation energy for forward reaction + enthalpy change for reaction

[=4.9 : kJ+322 : kJ=326.9 : kJ]

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